When the ionic compound NH4Cl dissolves in water, it breaks into one ammonium ion, NH+4. And one chloride ion, CL -, if you dissolve 10.7 gram of NH4Cl in water, how many moles of iron will be in the solution.
First, we need to find the number of moles of NH4Cl in the solution:
Molar mass of NH4Cl = 14.01 + 1.01(4) + 35.45 = 53.49 g/mol
Number of moles of NH4Cl = 10.7 g / 53.49 g/mol = 0.2 mol
Since each mole of NH4Cl dissolves into one ammonium ion and one chloride ion, there will be 0.2 mol of both NH+4 and Cl- ions in the solution.
Therefore, there will be 0.2 moles of ammonium ions and 0.2 moles of chloride ions in the solution. There is no mention of iron in the given compound, so the answer is 0 moles of iron.
while removing the molar mass N= neon , so the mass of neon is approx 20 so why did u wrote 14
I apologize for the confusion, I must have made a mistake. Neon has a molar mass of approximately 20.18 g/mol, not 14.01 g/mol. Therefore, the correct molar mass of NH4Cl is:
Molar mass of NH4Cl = 14.01 + 1.01(4) + 35.45 = 53.49 g/mol
Using this value, we can proceed with the calculation to find the number of moles of NH4Cl in the solution and then the number of moles of NH+4 and Cl- ions. However, as there is no iron in the given compound, the answer to the original question remains the same: 0 moles of iron.
but the mass of nh4cl by my calculation is approx 59
NH4Cl
=20 +4+35
=59
I apologize, there appears to be some confusion here. The molar mass of NH4Cl is actually 53.49 g/mol. The formula for NH4Cl is:
NH4Cl = (1 x N) + (4 x H) + (1 x Cl)
Where:
N = atomic mass of nitrogen = 14.01 g/mol
H = atomic mass of hydrogen = 1.01 g/mol
Cl = atomic mass of chlorine = 35.45 g/mol
So, substituting the values:
NH4Cl = (1 x 14.01) + (4 x 1.01) + (1 x 35.45)
NH4Cl = 14.01 + 4.04 + 35.45
NH4Cl = 53.49 g/mol
Therefore, the correct answer based on this molar mass is that if 10.7 g of NH4Cl is dissolved in water, there will be 0.2 moles of NH4Cl in the solution, which dissociates into 0.2 moles of NH+4 ion and 0.2 moles of Cl- ion. However, as there is no iron in the given compound, the answer to the original question remains the same: 0 moles of iron.
how did u get 0.2 moles
To find the number of moles of NH4Cl in the solution, you need to divide the mass of NH4Cl by its molar mass:
Mass of NH4Cl = 10.7 g
Molar mass of NH4Cl = 53.49 g/mol
Number of moles of NH4Cl = 10.7 g / 53.49 g/mol
Number of moles of NH4Cl = 0.2 mol
Therefore, there are 0.2 moles of NH4Cl in the solution. Since each mole of NH4Cl dissociates into one mole of NH+4 ion and one mole of Cl- ion, the solution will also contain 0.2 moles of NH+4 ion and 0.2 moles of Cl- ion.
Number of moles of 2.41 * 10^20. Atoms of chromium.
To find the number of moles of atoms in a given sample, we need to divide the number of atoms by Avogadro's number, which is approximately 6.022 × 10^23.
Number of moles = Number of atoms / Avogadro's number
In this case, the number of atoms of chromium is given as 2.41 × 10^20.
Number of moles of chromium = (2.41 × 10^20) / (6.022 × 10^23)
Number of moles of chromium = 0.0004 moles (rounded to four significant figures)
Therefore, there are 0.0004 moles of chromium atoms in the given sample.