When the ionic compound NH4Cl dissolves in water, it breaks into one ammonium ion, NH+4. And one chloride ion, CL -, if you dissolve 10.7 gram of NH4Cl in water, how many moles of iron will be in the solution.

First, we need to find the number of moles of NH4Cl in the solution:

Molar mass of NH4Cl = 14.01 + 1.01(4) + 35.45 = 53.49 g/mol
Number of moles of NH4Cl = 10.7 g / 53.49 g/mol = 0.2 mol

Since each mole of NH4Cl dissolves into one ammonium ion and one chloride ion, there will be 0.2 mol of both NH+4 and Cl- ions in the solution.

Therefore, there will be 0.2 moles of ammonium ions and 0.2 moles of chloride ions in the solution. There is no mention of iron in the given compound, so the answer is 0 moles of iron.

while removing the molar mass N= neon , so the mass of neon is approx 20 so why did u wrote 14

I apologize for the confusion, I must have made a mistake. Neon has a molar mass of approximately 20.18 g/mol, not 14.01 g/mol. Therefore, the correct molar mass of NH4Cl is:

Molar mass of NH4Cl = 14.01 + 1.01(4) + 35.45 = 53.49 g/mol

Using this value, we can proceed with the calculation to find the number of moles of NH4Cl in the solution and then the number of moles of NH+4 and Cl- ions. However, as there is no iron in the given compound, the answer to the original question remains the same: 0 moles of iron.

but the mass of nh4cl by my calculation is approx 59

NH4Cl
=20 +4+35
=59

I apologize, there appears to be some confusion here. The molar mass of NH4Cl is actually 53.49 g/mol. The formula for NH4Cl is:

NH4Cl = (1 x N) + (4 x H) + (1 x Cl)

Where:
N = atomic mass of nitrogen = 14.01 g/mol
H = atomic mass of hydrogen = 1.01 g/mol
Cl = atomic mass of chlorine = 35.45 g/mol

So, substituting the values:

NH4Cl = (1 x 14.01) + (4 x 1.01) + (1 x 35.45)
NH4Cl = 14.01 + 4.04 + 35.45
NH4Cl = 53.49 g/mol

Therefore, the correct answer based on this molar mass is that if 10.7 g of NH4Cl is dissolved in water, there will be 0.2 moles of NH4Cl in the solution, which dissociates into 0.2 moles of NH+4 ion and 0.2 moles of Cl- ion. However, as there is no iron in the given compound, the answer to the original question remains the same: 0 moles of iron.

how did u get 0.2 moles

To find the number of moles of NH4Cl in the solution, you need to divide the mass of NH4Cl by its molar mass:

Mass of NH4Cl = 10.7 g
Molar mass of NH4Cl = 53.49 g/mol

Number of moles of NH4Cl = 10.7 g / 53.49 g/mol
Number of moles of NH4Cl = 0.2 mol

Therefore, there are 0.2 moles of NH4Cl in the solution. Since each mole of NH4Cl dissociates into one mole of NH+4 ion and one mole of Cl- ion, the solution will also contain 0.2 moles of NH+4 ion and 0.2 moles of Cl- ion.

Number of moles of 2.41 * 10^20. Atoms of chromium.

To find the number of moles of atoms in a given sample, we need to divide the number of atoms by Avogadro's number, which is approximately 6.022 × 10^23.

Number of moles = Number of atoms / Avogadro's number

In this case, the number of atoms of chromium is given as 2.41 × 10^20.

Number of moles of chromium = (2.41 × 10^20) / (6.022 × 10^23)
Number of moles of chromium = 0.0004 moles (rounded to four significant figures)

Therefore, there are 0.0004 moles of chromium atoms in the given sample.

can u show me proper calculation of Number of moles of chromium = (2.41 × 10^20) / (6.022 × 10^23) plzzz

Yes, of course. Here is how to properly calculate the number of moles of chromium:

Number of moles of chromium = Number of atoms of chromium / Avogadro's number

Substituting the given values:

Number of moles of chromium = (2.41 × 10^20) / (6.022 × 10^23)

To divide these two numbers, we can simplify the calculation by multiplying by a factor of 1 that is equal to 1, but has units that cancel each other out. For example, we can use the conversion factor "1 mol / 6.022 × 10^23 atoms", which equals 1 because it's just another way to express Avogadro's number:

Number of moles of chromium = (2.41 × 10^20 atoms) x (1 mol / 6.022 × 10^23 atoms)
Number of moles of chromium = 0.000400 mol

Therefore, the number of moles of chromium in the given sample is 0.000400 mol (rounded to four significant figures).

i still did'nt understood

No problem, I will explain in more detail.

The number of moles of a substance is a measure of the amount of that substance. It is defined as the number of particles (atoms, molecules, or ions) divided by Avogadro's number, which is approximately 6.022 × 10^23. So, to calculate the number of moles of chromium in a sample containing 2.41 × 10^20 atoms of chromium, we use the following formula:

Number of moles of chromium = Number of atoms of chromium / Avogadro's number

In this formula, "Number of atoms of chromium" represents the given amount of chromium in the sample, which is 2.41 × 10^20 atoms.

To solve for the number of moles, we simply divide the number of atoms by Avogadro's number. This gives us:

Number of moles of chromium = (2.41 × 10^20) / (6.022 × 10^23)

This expression can be simplified by using the fact that dividing by a number is the same as multiplying by its reciprocal, or inverse. In this case, the reciprocal of Avogadro's number is 1 / (6.022 × 10^23), so we have:

Number of moles of chromium = (2.41 × 10^20) x (1 / 6.022 × 10^23)

Multiplying the two numbers, we get:

Number of moles of chromium = 0.000400 (rounded to four significant figures)

Therefore, if a sample contains 2.41 × 10^20 atoms of chromium, it contains 0.000400 moles of chromium.

i under stood every thing accept this calculation Number of moles of chromium = (2.41 × 10^20) x (1 / 6.022 × 10^23)

I'm sorry for the confusion. In the expression "Number of moles of chromium = (2.41 × 10^20) x (1 / 6.022 × 10^23)", we are multiplying the number of atoms of chromium (2.41 × 10^20) by the multiplicative inverse of Avogadro's number (1/(6.022 × 10^23)), which is equal to 1 divided by Avogadro's number.

This multiplication gives:

Number of moles of chromium = 0.000400 (rounded to four significant figures)

So, by dividing the number of atoms of chromium in the sample by Avogadro's number, we are able to determine the number of moles of chromium that are present.

I hope this clears up any confusion or misunderstandings, and please let me know if you have any further questions!