What is the total surface area of a cuboid whose dimensions are 11cm,8cm,5cm
The total surface area of a cuboid is given by the formula 2(lw+wh+lh), where l, w, and h are the length, width, and height of the cuboid, respectively.
Substituting the given values, we get:
2(11*8 + 8*5 + 11*5)
= 2(88 + 40 + 55)
= 2(183)
= 366
Therefore, the total surface area of the cuboid is 366 square centimeters.
To find the total surface area of a cuboid, you need to sum up the areas of all six faces.
Step 1: Identify the dimensions of the cuboid
Length (l) = 11 cm
Width (w) = 8 cm
Height (h) = 5 cm
Step 2: Calculate the area of each face
The formula to calculate the area of a rectangle is Area = Length × Width.
a) Area of the front and back faces: 2lw
Front face = 11 cm × 5 cm = 55 cm²
Back face = 11 cm × 5 cm = 55 cm²
b) Area of the top and bottom faces: 2lh
Top face = 11 cm × 8 cm = 88 cm²
Bottom face = 11 cm × 8 cm = 88 cm²
c) Area of the left and right faces: 2wh
Left face = 8 cm × 5 cm = 40 cm²
Right face = 8 cm × 5 cm = 40 cm²
Step 3: Add up all the areas
Total surface area = 2lw + 2lh + 2wh
Total surface area = 55 cm² + 55 cm² + 88 cm² + 88 cm² + 40 cm² + 40 cm²
Total surface area = 366 cm²
Therefore, the total surface area of the given cuboid is 366 cm².