The half life of 24Na is 15.0hr . how long does it take for 80 percent of a sample nuclide to decay
Using the half-life formula, we can find the amount of time it takes for 80 percent of the sample nuclide to decay:
t = (t1/2) x log(0.2)/log(0.5)
t = (15.0hr) x log(0.2)/log(0.5)
t = (15.0hr) x 2.32
t = 34.8 hours
Therefore, it takes 34.8 hours for 80 percent of a sample nuclide of 24Na to decay.
To determine how long it takes for 80 percent of a sample nuclide to decay, you can use the concept of half-life.
The half-life of a nuclide is the time it takes for half of the sample to decay. In this case, the half-life of 24Na is given as 15.0 hours.
Now, let's calculate how many half-lives it would take for 80 percent of the sample to decay.
80 percent is equivalent to 0.80.
To calculate the number of half-lives needed, we can use the formula:
Number of Half-Lives = Log (initial amount) / Log (0.5)
Assuming we start with 100% of the sample, the initial amount is 1.
Number of Half-Lives = Log (1) / Log (0.5)
Number of Half-Lives = 0 / (-0.301)
Number of Half-Lives = 0
Since the result is 0, we conclude that it would take 0 half-lives for 80 percent of the sample to decay.
Therefore, 80 percent of the sample would decay instantly; there would be no time delay.