Calculate the binding energy per nucleons, in MeV, for 3/2with a mass of 3.016029u.
The total mass of the nucleus is 3.016029 u = 3.016029 * 931.5 = 2808.920535 MeV/c².
The mass of 3/2 is (3/2) * 1.007825 u = 1.511738 MeV/c².
The binding energy of the nucleus is the difference between the total mass and the mass of the protons and neutrons:
Binding energy = (3 * 1.007276 u + 1 * 1.008665 u - 3.016029 u) * 931.5 MeV/u = 26.2288735 MeV
The number of nucleons is 4, so the binding energy per nucleons is:
Binding energy per nucleons = 26.2288735 MeV / 4 = 6.557218375 MeV/nucleon
Therefore, the binding energy per nucleons for 3/2 with a mass of 3.016029u is 6.557218375 MeV/nucleon.
To calculate the binding energy per nucleon, we need to know the total mass of the nucleus and the number of nucleons in the nucleus.
Given:
Mass of the nucleus, m = 3.016029 u
Number of nucleons, A = 3/2
Note: The mass unit 'u' is atomic mass unit, and '3/2' is an invalid number of nucleons. Please provide the correct number of nucleons for accurate calculation.
If you provide the correct number of nucleons, I can help you calculate the binding energy per nucleon.