What volume of ethanol in a litre (L) having a density of 0.678 g/cm3 can be poured into a graduated cylinder to give 16.28 g of alcohol?
First, we need to convert the density of ethanol from g/cm3 to g/mL:
0.678 g/cm3 = 0.678 g/mL
Next, we can use the formula:
volume = mass / density
to calculate the volume of ethanol needed:
volume = 16.28 g / 0.678 g/mL
volume = 24.03 mL
Finally, we can convert mL to L by dividing by 1000:
volume = 24.03 mL / 1000
volume = 0.024 L
Therefore, 0.024 L of ethanol can be poured into the graduated cylinder to give 16.28 g of alcohol.
To find the volume of ethanol needed, we can use the formula:
Volume = Mass / Density
Given:
Density of ethanol = 0.678 g/cm³
Mass of ethanol = 16.28 g
Let's calculate the volume:
Volume = 16.28 g / 0.678 g/cm³
To proceed with the calculation, we need to convert the units to ensure they are consistent. Since the density is given in grams per cubic centimeter (g/cm³), we need to convert the mass to grams as well.
Now, let's calculate the volume:
Volume = 16.28 g / 0.678 g/cm³
Volume ≈ 24.0 cm³
Therefore, approximately 24.0 cm³ (or mL) of ethanol is needed to produce 16.28 g of alcohol.