The density of aluminum is 2.70g/cm3. What volume (in cm3) does 3.00kg occupy?
We can use the formula:
density = mass / volume
To find the volume, we rearrange the formula:
volume = mass / density
Plugging in the values:
volume = 3.00kg / 2.70g/cm3
We must make sure the units are consistent. We can convert the mass to grams:
volume = 3000g / 2.70g/cm3
Simplifying:
volume = 1111.11 cm3
Therefore, 3.00 kg of aluminum occupies 1111.11 cm3.
To find the volume occupied by 3.00 kg of aluminum, we can use the density of aluminum.
The density of aluminum is given as 2.70 g/cm^3.
We can rearrange the formula for density to solve for volume:
Density = mass/volume
So, volume = mass/density.
Given that the mass is 3.00 kg, we first need to convert it to grams:
1 kg = 1000 g
Therefore, 3.00 kg = 3.00 * 1000 g = 3000 g.
Now we can calculate the volume:
volume = mass/density = 3000 g / 2.70 g/cm^3.
Simplifying this, we find:
volume = 1111.11 cm^3.
Therefore, 3.00 kg of aluminum occupies a volume of 1111.11 cm^3.
To find the volume occupied by aluminum, we can use the formula:
Density = Mass / Volume
We are given the density of aluminum as 2.70 g/cm^3 and the mass as 3.00 kg. However, the mass needs to be converted to grams before applying the formula. We know that 1 kg is equal to 1000 g.
Converting the mass:
3.00 kg * 1000 g/kg = 3000 g
Now we can rearrange the formula to solve for the volume:
Volume = Mass / Density
Plugging in the values:
Volume = 3000 g / 2.70 g/cm^3
Canceling out the units of grams:
Volume = 3000 / 2.70 cm^3
Simplifying:
Volume ≈ 1111.11 cm^3 (rounded to two decimal places)
Therefore, 3.00 kg of aluminum occupies approximately 1111.11 cm^3.