What is the probability of rolling an odd number on the first roll of a six-sided cube and rolling an even number on the second roll?
Answers:
2
1/2
1/4
1
/2
There are three odd numbers (1, 3, 5) and three even numbers (2, 4, 6) on a six-sided cube. The probability of rolling an odd number on the first roll is 3/6 or 1/2. The probability of rolling an even number on the second roll is also 3/6 or 1/2. To find the probability of both events happening, we multiply the probabilities together: 1/2 x 1/2 = 1/4. Therefore, the answer is C) 1/4.
To find the probability of rolling an odd number on the first roll of a six-sided cube and rolling an even number on the second roll, we need to determine the probability of each event and then multiply the probabilities together.
Event 1: Rolling an odd number on the first roll.
Since there are three odd numbers (1, 3, and 5) on a six-sided cube, and a total of six possible outcomes, the probability of rolling an odd number on the first roll is 3/6 or 1/2.
Event 2: Rolling an even number on the second roll.
Since there are three even numbers (2, 4, and 6) on a six-sided cube, and a total of six possible outcomes, the probability of rolling an even number on the second roll is 3/6 or 1/2.
To calculate the probability of both events occurring, we multiply the probabilities together:
(1/2) * (1/2) = 1/4.
Therefore, the probability of rolling an odd number on the first roll of a six-sided cube and rolling an even number on the second roll is 1/4.