What is the probability of rolling an odd number on the first roll of a six-sided cube and rolling an even number on the second roll?
The probability of rolling an odd number on the first roll is 3/6 (since there are three odd numbers out of six total). Then, assuming the first roll was odd, the probability of rolling an even number on the second roll is 3/5 (since there are three even numbers remaining out of five total). Therefore, the overall probability is:
(3/6) x (3/5) = 9/30 = 3/10
So, the probability of rolling an odd number on the first roll and an even number on the second roll is 3/10.
To find the probability of rolling an odd number on the first roll of a six-sided cube and rolling an even number on the second roll, we need to consider the total number of possible outcomes and the number of favorable outcomes.
Total number of possible outcomes when rolling a six-sided cube = 6 (because the cube has six sides labeled with numbers 1 to 6).
Number of favorable outcomes for the first roll (odd number) = 3 (since there are three odd numbers on the cube: 1, 3, and 5).
Number of favorable outcomes for the second roll (even number) = 3 (since there are three even numbers on the cube: 2, 4, and 6).
To find the probability, we divide the number of favorable outcomes by the total number of possible outcomes:
Probability = (Number of favorable outcomes) / (Total number of possible outcomes)
Probability = (3 * 3) / (6 * 6)
Probability = 9 / 36
Probability = 1/4
Therefore, the probability of rolling an odd number on the first roll of a six-sided cube and rolling an even number on the second roll is 1/4 or 25%.