What the mass of Naso4 is produced if 49g of H2s4 react 80g of Naoh?
The balanced chemical equation for the reaction between H2SO4 and NaOH is:
H2SO4 + 2NaOH -> Na2SO4 + 2H2O
According to the equation, one mole of H2SO4 reacts with two moles of NaOH to produce one mole of Na2SO4 and two moles of H2O.
First, we need to determine the limiting reactant in the given reaction. We can do this by calculating the amount in moles of each reactant and comparing their ratios.
The molar mass of H2SO4 is 98 g/mol, therefore 49 g of H2SO4 is equal to:
49 g / 98 g/mol = 0.5 mol H2SO4
The molar mass of NaOH is 40 g/mol, therefore 80 g of NaOH is equal to:
80 g / 40 g/mol = 2 mol NaOH
The ratio of moles of H2SO4 to NaOH is 0.5:2, or 1:4. This means that NaOH is in excess and H2SO4 is the limiting reactant.
To calculate the mass of Na2SO4 produced, we need to use the mole ratio between H2SO4 and Na2SO4. The ratio from the balanced equation is 1:1, which means that 0.5 mol of Na2SO4 is produced.
The molar mass of Na2SO4 is 142 g/mol, therefore the mass of Na2SO4 produced is:
0.5 mol x 142 g/mol = 71 g
Therefore, 71 g of Na2SO4 is produced when 49g of H2SO4 reacts with 80g of NaOH.
To determine the mass of NaSO4 produced, we first need to write and balance the chemical equation for the reaction between H2SO4 and NaOH:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
According to the balanced equation, one mole of H2SO4 reacts with 2 moles of NaOH to produce one mole of Na2SO4.
Let's calculate the number of moles of H2SO4 and NaOH given the mass of each substance:
Step 1: Calculate moles of H2SO4:
Molar mass of H2SO4 = (2 × 1.01 g/mol of H) + (32.07 g/mol of S) + (4 × 16.00 g/mol of O)
= 98.09 g/mol
Number of moles of H2SO4 = Mass of H2SO4 / Molar mass of H2SO4
= 49 g / 98.09 g/mol
= 0.5 mol
Step 2: Calculate moles of NaOH:
Molar mass of NaOH = (22.99 g/mol of Na) + (16.00 g/mol of O) + (1.01 g/mol of H)
= 39.99 g/mol
Number of moles of NaOH = Mass of NaOH / Molar mass of NaOH
= 80 g / 40 g/mol
= 2 mol
Step 3: Based on the balanced equation, the mole ratio between H2SO4 and Na2SO4 is 1:1. So, the number of moles of Na2SO4 produced is also 0.5 mol.
Step 4: Calculate the mass of Na2SO4 produced:
Molar mass of Na2SO4 = (22.99 g/mol of Na) +(32.07 g/mol of S) + (4 × 16.00 g/mol of O)
= 142.04 g/mol
Mass of Na2SO4 produced = Number of moles of Na2SO4 × Molar mass of Na2SO4
= 0.5 mol × 142.04 g/mol
= 71.02 g
Therefore, the mass of Na2SO4 produced when 49g of H2SO4 reacts with 80g of NaOH is 71.02 g.