a random sample of 40 students from each grade level were surveyed regarding their preferences for a class trip use the table below to answer questions three and four.
7th grade preferred the zoo 12 museum 18 sports complex 10
Eighth grade preferred the zoo 14 museum 19 sports complex 7
3.) if there are 220 members of the 7th grade class how many students can be expected to prefer the zoo ?a.)39 b.)48 c.)120 d.)66
4.) if they're 180 members of the 8th grade class then what percentage preferred either the museum or the sports complex ?
a.)65% b.)47.5% c.)17.5% d.) 26%
3.) The number of 7th grade students who preferred the zoo can be calculated as: (12/40)*40 = 12. Therefore, if there are 220 members of the 7th grade class, the number of students who can be expected to prefer the zoo is: (12/40)*220 = 66. Answer: d.)
4.) The number of 8th grade students who preferred the museum or sports complex can be calculated as: 19+7 = 26. Therefore, the percentage of 8th grade students who preferred either the museum or sports complex is: (26/40)*100% = 65%. Answer: a.)
Two friends measure the distance of a race car travels over 10 trials. Use the data to answer the questions five and six.
Jamal
2 at 5 ft 4 at 6 ft 2 at 7 ft 1 at 8 ft and one at 10 ft
Kendalls
1 at 7 ft 1 at 8 ft 3 at 9 ft 4 at 10 ft 1at 11 ft
5.) Which of the conclusions best supports the dot plots?
A.) both Jamal's and Kendall's race cars had an equal spread in their data
B.) on average Kendalls race car traveled further.
C.) the median distance Jamal's race car traveled was 6.5 ft
D. both Jamal and Kendall's had the same mode of data.
6.) Which of the following represents the mean absolute devitation of Jamal's data?
A.) 6.4
B.) 1.12
C.) 2.8
D.) 0.9
5.) One way to compare the data sets is to look at the central tendency measures. The mean distance traveled by Jamal's race car is (2*5 + 4*6 + 2*7 + 1*8 + 1*10)/10 = 6.1 ft. The mean distance traveled by Kendall's race car is (1*7 + 1*8 + 3*9 + 4*10 + 1*11)/10 = 9.3 ft. Therefore, it can be concluded that, on average, Kendall's race car traveled further. Answer: B.)
6.) To calculate the mean absolute deviation (MAD) of Jamal's data, follow these steps:
- Find the mean of the data: (2*5 + 4*6 + 2*7 + 1*8 + 1*10)/10 = 6.1 ft
- Find the absolute deviation of each data point by subtracting the mean from it and taking the absolute value: |5-6.1|, |5-6.1|, |6-6.1|, |6-6.1|, |6-6.1|, |6-6.1|, |7-6.1|, |7-6.1|, |8-6.1|, |10-6.1|
- Find the mean of the absolute deviations: (0.1+0.1+0.1+0.1+0.1+0.1+0.9+0.9+1.9+3.9)/10 = 1.12 ft
Therefore, the mean absolute deviation of Jamal's data is 1.12 ft. Answer: B.)
God has collected from a random sample of 40 people at the public library public library has 300 patrons then which of the following conclusions can be drawn?nonfiction 12 mystery 18 sci-fi 10
A. Exactly 42% of the library patrons chose mystery.
B. Nonfiction and science fiction represent over half of the selection
C. Over 25% of the library patrons choose a science fiction book.
D. 136 total patrons can be expected to choose a nonfiction book
To draw conclusions about the entire population of the library patrons, we need to scale up the results based on the proportion of the sample size to the population size.
A. The proportion of the sample that chose mystery is 18/40 = 0.45 or 45%. To scale up, we can multiply by the total number of patrons in the library: 0.45 * 300 = 135. Therefore, we cannot conclude that exactly 42% of the library patrons chose a mystery book. Answer: None of the above.
B. The total number of nonfiction and sci-fi books chosen in the sample is 12+10 = 22. The proportion of the sample that chose nonfiction or sci-fi is 22/40 = 0.55 or 55%. To scale up, we can multiply by the total number of patrons in the library: 0.55 * 300 = 165. Therefore, we can conclude that nonfiction and science fiction books represent over half of the selection. Answer: B.
C. The proportion of the sample that chose science fiction is 10/40 = 0.25 or 25%. To scale up, we can multiply by the total number of patrons in the library: 0.25 * 300 = 75. Therefore, we can conclude that over 25% of the library patrons chose a science fiction book. Answer: C.
D. The proportion of the sample that chose nonfiction is 12/40 = 0.3 or 30%. To scale up, we can multiply by the total number of patrons in the library: 0.3 * 300 = 90. Therefore, we can conclude that 90 total patrons can be expected to choose a nonfiction book. Answer: D.
Data is collected from a random sample of 40 people at the public library. If the public library has 300 patrons then which of the following conclusions can be drawn? Use the data below for library patrons nonfiction- 12, mystery-18, sci-fi -10
A. Exactly 42% of the library patrons chose mystery.
B. Nonfiction and science fiction represent over half of the selection
C. Over 25% of the library patrons choose a science fiction book.
D. 136 total patrons can be expected to choose a nonfiction book
To draw conclusions about the entire population of the library patrons, we need to scale up the results based on the proportion of the sample size to the population size.
A. The proportion of the sample that chose mystery is 18/40 = 0.45 or 45%. To scale up, we can multiply by the total number of patrons in the library: 0.45 * 300 = 135. Therefore, we cannot conclude that exactly 42% of the library patrons chose a mystery book. Answer: None of the above.
B. The total number of nonfiction and sci-fi books chosen in the sample is 12+10 = 22. The proportion of the sample that chose nonfiction or sci-fi is 22/40 = 0.55 or 55%. To scale up, we can multiply by the total number of patrons in the library: 0.55 * 300 = 165. Therefore, we can conclude that nonfiction and science fiction books represent over half of the selection. Answer: B.
C. The proportion of the sample that chose science fiction is 10/40 = 0.25 or 25%. To scale up, we can multiply by the total number of patrons in the library: 0.25 * 300 = 75. Therefore, we can conclude that over 25% of the library patrons chose a science fiction book. Answer: C.
D. The proportion of the sample that chose nonfiction is 12/40 = 0.3 or 30%. To scale up, we can multiply by the total number of patrons in the library: 0.3 * 300 = 90. Therefore, we can conclude that 90 total patrons can be expected to choose a nonfiction book. Answer: D.
Need to only pick one that can be drawn from the data set A B C or D?
My apologies for the confusion. To clarify, the correct answer is:
B. Nonfiction and science fiction represent over half of the selection.
This conclusion can be drawn by scaling up the proportion of the sample that chose nonfiction or sci-fi (22/40 or 0.55) to the total number of patrons in the library (300). This results in 0.55 * 300 = 165, which is over half of the total number of selections. Therefore, B is the correct answer.
The data from two random samples of 100 students regarding what pet they own is given below.
Sample 1: dog-54, cat-38, bird-8 total -100
Sample 2: dog-39, cat-49, bird -12 total -100
based on the two samples what percentage of students own a bird as a pet?
____%