Carol asked a random sample of 10 seventh grade student athletes and 10 seventh grade students who are not athletes how much time, in minutes, they spend studying each weeknight. She recorded her results in the table.
103 62 21 100 140
65 124 45 86 114
101 135 122 43 110
62 31 80 67 126
Calculate the mean and median data values for the student athletes sample.
Calculate the mean and median data values for the not student athletes sample.
When comparing the two samples, what conclusions can you draw about which group spends more time studying each weeknight?
STUDENT ATHLETES:
MEAN: 83
MEDIAN: 90
NOT STUDENT ATHLETES:
MEAN: 85
MEDIAN: 90
So find the mean, and median values for each set : )
Remember.. the means is add them all up and divide by the number in the set.
While the median is arrange each set from smallest to biggest and find the middle piece of data : )
Because I got STUDENT ATHLETES MEAN is 86 and the MEDIAN 93. The NON STUDENT ATHLETES MEDIAN is 90.5 and the MEAN 87.7
he is correct
Is he correct?
not sure but i assume
The answer is a. mean=86 and median=93
b. mean=87.7 and median=90.5
c. The mean for non-athletes is 1.7 minutes greater than for the athletes and the median for athletes is 2.5 minutes greater than for the non-athletes. So, it is too close to draw a conclusion at this point.
REWORD IT!!
To calculate the mean and median data values for each sample, we need to first find the sum of the values in each sample and then divide it by the total number of values.
For the athlete sample:
Sum of values = 103 + 62 + 21 + 100 + 140 + 65 + 124 + 45 + 86 + 114 = 960
Mean = Sum of values / Number of values = 960 / 10 = 96
To find the median, we need to arrange the values in ascending order:
21, 31, 43, 45, 62, 62, 65, 80, 86, 100, 103, 110, 114, 124, 126, 135, 140
Since we have an even number of values, we take the average of the middle two values:
(86 + 100) / 2 = 93
For the not athlete sample:
Sum of values = 101 + 135 + 122 + 43 + 110 + 62 + 31 + 80 + 67 + 126 = 877
Mean = Sum of values / Number of values = 877 / 10 = 87.7
To find the median, we need to arrange the values in ascending order:
31, 43, 62, 67, 80, 101, 110, 122, 126, 135
Since we have an odd number of values, the median is the middle value:
Median = 101
When comparing the two samples, we can conclude that the student athletes sample has a higher mean (96 vs 87.7) and a higher median (93 vs 101) study time. Therefore, we can infer that the student athletes spend more time studying each weeknight compared to the non-athlete students.