What is the phase difference between input and output voltages?
supply voltages = ±12V
amplitude =100mV
frequency = 500Hz
r1 = 1 kΩ
r2 = 27 kΩ
vcc = 12v
vee = 12v
Av = vout/vin = ?
Av (db) = 20 log(vout/vin) = ?
𝑃ℎ𝑎𝑠𝑒 𝐷𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒 (𝜑) = ?
We need to know the circuit configuration to determine the phase difference between input and output voltages. Without this information, we cannot calculate the phase difference.
vin = 100mVpk, 500 hz
r1 = 1 kΩ
r2 = 27 kΩ
vcc = 12v
vee = 12v
Av = vout/vin = ?
Av (db) = 20 log(vout/vin) = ?
𝑃ℎ𝑎𝑠𝑒 𝐷𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒 (𝜑) = ?
The given circuit is an inverting amplifier configuration.
Av = -R2/R1 = -27kΩ/1kΩ = -27
Av (db) = 20 log(|Av|) = 20 log(27) = 30.6 dB
The phase difference between the input and output voltages in an inverting amplifier is 180 degrees or π radians. Therefore, the phase difference is 𝜑 = π.
To determine the phase difference between input and output voltages, we first need to calculate the voltage gain (Av) of the system.
Given data:
supply voltage = ±12V
amplitude = 100mV
frequency = 500Hz
r1 = 1 kΩ
r2 = 27 kΩ
vcc = 12V
vee = 12V
To find Av, we can use the voltage division formula since we have a resistive voltage divider circuit:
Av = vout / vin = (r2 / (r1 + r2))
Substituting the respective values, we obtain:
Av = (27 kΩ / (1 kΩ + 27 kΩ)) = 27 kΩ / 28 kΩ = 0.9643
To find Av in decibels, we use the formula:
Av(db) = 20 * log10(Av)
Plugging in the value of Av, we get:
Av(db) = 20 * log10(0.9643) ≈ -0.81 dB
Now, to determine the phase difference (φ), we need some additional information about the input and output signals. The given data does not provide any phase information. If we have the phase shift information, we can calculate φ using the following formula:
φ = 360 * (Δt / T)
Where:
φ = phase difference in degrees
Δt = time shift (delay) between input and output signals
T = period or time period of the waveform
Since we don't have information on Δt or T, it is not possible to calculate the phase difference (φ) with the given data.