80-5x^2=0 use factorization to solve for the unknown
We can begin factoring by factoring out a common factor of 5:
5(16-x^2) = 0
Now we have a difference of squares, which we can factor as:
5(4+x)(4-x) = 0
This equation will be true if any of the factors are equal to zero. Therefore, we have two solutions:
4+x = 0 or 4-x = 0
Solving for x in each case, we get:
x = -4 or x = 4
Therefore, the solutions to the equation 80-5x^2=0 are x=-4 and x=4.