3c^2-18c +15=0 use factorization to solve for the unknown
We can start by finding two numbers whose product is 3c^2 and whose sum is -18c. These two numbers are -3c and -5c, because (-3c)(-5c)=15c^2 and (-3c)+(-5c)=-8c.
So we can rewrite the equation as:
3c^2 - 3c - 15c + 15 = 0
Now we can factor by grouping the first two terms and the last two terms:
(3c^2 - 3c) - (15c - 15) = 0
3c(c - 1) - 15(c - 1) = 0
(3c - 15)(c - 1) = 0
Now we can solve for c by setting each factor equal to zero:
3c - 15 = 0 or c - 1 = 0
3c = 15 or c = 1
c = 5 or c = 1
Therefore, the solutions are c = 5 and c = 1.