How many gram of KCl are present in 85,0ml of 2,10m kCl?
To solve this problem, we can use the formula:
moles of solute = concentration x volume (in liters)
Then, we can convert moles to grams using the molar mass of KCl.
First, we need to convert the volume from milliliters to liters:
85.0 ml = 0.085 L
Next, we can plug in the given values:
moles of KCl = 2.10 mol/L x 0.085 L
moles of KCl = 0.1785 mol
Finally, we can convert moles of KCl to grams:
mass of KCl = moles of KCl x molar mass of KCl
mass of KCl = 0.1785 mol x 74.55 g/mol
mass of KCl = 13.3 g
Therefore, there are 13.3 grams of KCl present in 85.0 ml of 2.10 M KCl.
What is the molarity of a solution prepared by dissolving 5433g of ca(NO3)2 in 355ml of water?
To calculate the molarity of the solution, we need to first calculate the number of moles of Ca(NO3)2 present in the solution.
Number of moles = mass / molar mass
The molar mass of Ca(NO3)2 is:
Ca = 1 x 40.08 = 40.08 g/mol
N = 2 x 14.01 = 28.02 g/mol
O = 6 x 16.00 = 96.00 g/mol
Molar mass of Ca(NO3)2 = 164.10 g/mol
So, the number of moles of Ca(NO3)2 in the solution is:
Number of moles = 5433 g / 164.10 g/mol = 33.10 mol
Now, we need to calculate the volume of the solution in liters:
Volume = 355 ml / 1000 ml/L = 0.355 L
Finally, we can calculate the molarity of the solution using the formula:
Molarity = number of moles / volume of solution in liters
Molarity = 33.10 mol / 0.355 L = 93.1 M
Therefore, the molarity of the solution prepared by dissolving 5433 g of Ca(NO3)2 in 355 ml of water is 93.1 M.
To find out how many grams of KCl are present in 85.0 mL of a 2.10 M KCl solution, we can use the formula:
Mass (grams) = Volume (Liters) × Concentration (Molarity) × Formula Weight (g/mol)
First, let's convert the volume from milliliters to liters:
85.0 mL ÷ 1000 = 0.085 liters
Next, we need to calculate the number of moles of KCl in the solution using the molarity:
Moles of KCl = Volume (Liters) × Concentration (Molarity)
Moles of KCl = 0.085 L × 2.10 M = 0.1785 moles
Finally, we will use the formula weight of KCl to convert moles to grams:
Formula weight of KCl = 39.10 g/mol (atomic weight of K) + 35.45 g/mol (atomic weight of Cl)
Formula weight of KCl = 74.55 g/mol
Mass (grams) = Moles of KCl × Formula Weight (g/mol)
Mass (grams) = 0.1785 mol × 74.55 g/mol ≈ 13.32 grams
Therefore, there are approximately 13.32 grams of KCl present in 85.0 mL of the 2.10 M KCl solution.