A radio signal travels at
3
.
00
⋅
10
8
meters per second. How many seconds will it take for a radio signal to travel from a satellite to the surface of Earth if the satellite is orbiting at a height of
3
.
54
⋅
10
7
meters? Show your work.
We can use the formula:
distance = speed x time
The distance in this case is the height of the satellite above the surface of the Earth, which is 3.54 x 10^7 meters. The speed is the speed of light, which is 3.00 x 10^8 meters per second. We want to find the time it takes for the signal to travel from the satellite to the surface of the Earth, so we can rearrange the formula to:
time = distance / speed
Plugging in the values, we get:
time = 3.54 x 10^7 meters / (3.00 x 10^8 meters per second)
time = 0.118 seconds
Therefore, it takes approximately 0.118 seconds for a radio signal to travel from a satellite orbiting at a height of 3.54 x 10^7 meters to the surface of Earth.
The time taken by radio signal to reach on earth is 0.118 second
Correct, the time taken by a radio signal to travel from a satellite orbiting at a height of 3.54 x 10^7 meters to the surface of Earth is approximately 0.118 seconds.
To calculate the time it takes for a radio signal to travel from a satellite to the surface of the Earth, we can use the formula:
Time = Distance / Speed
Given that the speed of a radio signal is 3.00 × 10^8 meters per second, and the distance between the satellite and the surface of the Earth is 3.54 × 10^7 meters, we can substitute these values into the formula:
Time = (3.54 × 10^7 meters) / (3.00 × 10^8 meters per second)
Now, let's simplify this expression:
Time = 3.54 × 10^7 / 3.00 × 10^8
= (3.54 / 3.00) × (10^7 / 10^8)
= 1.18 × 10^(-1)
So, it will take approximately 0.118 seconds for a radio signal to travel from the satellite to the surface of the Earth.