Radio signals travel at a rate of 3 × 108 meters per second. How many seconds would it take for a radio signal to travel from a satellite to the surface of Earth if the satellite is orbiting at a height of 3.6 × 107 meters? (Hint: Time is distance divided by rate.)
To calculate the time it would take for a radio signal to travel from a satellite to the surface of Earth, we can use the formula:
Time = Distance / Rate
Given:
Distance = 3.6 × 10^7 meters
Rate = 3 × 10^8 meters per second
Time = (3.6 × 10^7) / (3 × 10^8)
Time = 0.12 seconds
Therefore, it would take 0.12 seconds for a radio signal to travel from a satellite orbiting at a height of 3.6 × 10^7 meters to the surface of Earth.
8.3 seconds 1.2 × 10–1 seconds 1.2 × 10 –1 seconds 1.08 × 1016 seconds 1.08 × 10 16 seconds 10.8 × 1015 seconds
I apologize for the error in my previous calculation. Let's re-calculate the time it would take for a radio signal to travel from a satellite to the surface of Earth:
Given:
Distance = 3.6 × 10^7 meters
Rate = 3 × 10^8 meters per second
Time = Distance / Rate
Time = (3.6 × 10^7) / (3 × 10^8)
Time = 0.12 seconds
Therefore, it would take 0.12 seconds for a radio signal to travel from a satellite orbiting at a height of 3.6 × 10^7 meters to the surface of Earth. So, the correct answer is:
1.2 × 10^−1 seconds