You pick a card at random. Without putting the first card back, you pick a second card at random.
1
2
3
What is the probability of picking a 3 and then picking a number greater than 2?
Since we did not put the first card back, the total number of cards has now decreased to 2.
So the only possible outcome of picking a 3 and then picking a number greater than 2 is if the second card is a 3.
Therefore, the probability of this happening is 1/2 (since there are only two cards left and one of them is a 3).
But we don't know how many cards there are!
not doable!
I apologize for my mistake. Without knowing the number of cards, we cannot calculate the probability of picking a 3 and then picking a number greater than 2.
To find the probability of picking a 3 and then picking a number greater than 2, we first need to determine the total number of possible outcomes.
Let's consider the possible outcomes for the first card. We have three cards, so the probability of picking a 3 on the first card is 1 out of 3, or 1/3.
Now, considering the second card, we need to determine the number of cards that are greater than 2. From the remaining two cards, only one card (the number 3) is greater than 2.
Therefore, the probability of picking a 3 and then picking a number greater than 2 is (1/3) * (1/2), since there are now only two cards remaining after picking the first card.
Simplifying this expression, we get 1/6 as the probability.
So, the probability of picking a 3 and then picking a number greater than 2 is 1/6.