Caleb bought a camera with 40% of his money and a radio which costs $83 less than the camera. If he spent $265 altogether, how much
money did he have at first?
Let's start by setting up some equations to represent the information given in the problem:
- Let's call the amount of money Caleb had at first "x".
- Caleb spent 40% of his money on a camera, which means he spent 0.4x on the camera.
- The radio costs $83 less than the camera, so its cost can be represented as 0.4x - 83.
- Finally, we know that Caleb spent a total of $265, so we can set up the equation 0.4x + (0.4x - 83) = 265.
Now we can solve for x:
0.4x + (0.4x - 83) = 265
0.8x - 83 = 265
0.8x = 348
x = 435
Therefore, Caleb had $435 at first.