below are the results of tossing a number cube nine times find the experimental probability of tossing a number 4,3,6,6,2,5,3,5,1
There are a couple of ways to approach this problem, but one common method is to count the number of times the desired outcome occurs and divide by the total number of trials.
In this case, we can see that the number 4 appears once, the number 3 appears twice, the number 6 appears twice, the number 2 appears once, and the number 5 appears twice and the number 1 appears once:
4, 3, 6, 6, 2, 5, 3, 5, 1
So the desired outcome occurred a total of 1 + 2 + 2 + 1 + 2 + 1 = 9 times out of 9 trials. Therefore, the experimental probability of tossing a number 4, 3, 6, 6, 2, 5, 3, 5, 1 is:
9/9 or 1 or 100% (rounded to the nearest whole percent)