Jerry wants to wrap a present in a box for his mother. The box measures 10 cm wide 4 cm high and 17 cm long. How much wrapping paper will Jerry need to wrap the present
First, we need to calculate the surface area of the box. To do so, we need to determine the area of each face of the box:
- The top and bottom faces are both rectangular, with dimensions 10 cm by 17 cm. The area of each face is therefore 10 cm x 17 cm = 170 cm^2.
- The front and back faces are both rectangular, with dimensions 4 cm by 17 cm. The area of each face is therefore 4 cm x 17 cm = 68 cm^2.
- The left and right faces are both rectangular, with dimensions 4 cm by 10 cm. The area of each face is therefore 4 cm x 10 cm = 40 cm^2.
To calculate the total surface area, we add up the area of all six faces:
170 cm^2 + 170 cm^2 + 68 cm^2 + 68 cm^2 + 40 cm^2 + 40 cm^2 = 556 cm^2
Therefore, Jerry will need 556 cm^2 of wrapping paper to wrap the present.
To calculate the amount of wrapping paper Jerry will need, we need to find the surface area of the box. The surface area of a rectangular prism (box) is given by the formula:
Surface Area = 2lw + 2lh + 2wh
Where:
l = length of the box
w = width of the box
h = height of the box
Given that:
l = 17 cm
w = 10 cm
h = 4 cm
Let's substitute the values into the formula and calculate the surface area:
Surface Area = 2(17)(10) + 2(17)(4) + 2(10)(4)
Surface Area = 340 + 136 + 80
Surface Area = 556 cm²
Therefore, Jerry will need 556 cm² of wrapping paper to wrap the present.
To find out how much wrapping paper Jerry will need, we need to calculate the surface area of the box. The surface area of a rectangular box can be calculated by adding the areas of all six faces of the box.
The box has three pairs of faces with the same dimensions:
- The front and back faces have dimensions 10 cm x 4 cm.
- The top and bottom faces have dimensions 10 cm x 17 cm.
- The left and right faces have dimensions 4 cm x 17 cm.
To calculate the area of each face, multiply the length by width. Then, add all six areas to find the total surface area of the box.
Front and back faces: 10 cm x 4 cm = 40 cm² each
Top and bottom faces: 10 cm x 17 cm = 170 cm² each
Left and right faces: 4 cm x 17 cm = 68 cm² each
Total surface area: (2 x 40 cm²) + (2 x 170 cm²) + (2 x 68 cm²) = 80 cm² + 340 cm² + 136 cm² = 556 cm²
So, Jerry will need 556 cm² of wrapping paper to wrap the present.