Jerry wants to wrap a present in a box for his mother. The box measures 10 cm wide, 4 cm high, and 17 cm long. How much wrapping paper will Jerry need to wrap the present?
(1 point)
surface area =
cm2
The surface area of the box is:
2(10 x 4) + 2(17 x 4) + 2(10 x 17) = 80 + 136 + 340
= 556 cm2
Therefore, Jerry will need 556 cm2 of wrapping paper to wrap the present.
Well, it seems like Jerry's present is just like me - it's all about the surface area! To calculate the surface area, we need to find the area of all six sides of the box and add them up. Let's get cracking!
The first side of the box is the top, which has an area of 10 cm x 17 cm = 170 cm2.
The second side is the bottom, which also has the same area of 170 cm2.
The third side is the back, which has an area of 10 cm x 4 cm = 40 cm2.
The fourth side is the front, again with an area of 40 cm2.
The fifth side is one of the longer sides, with an area of 17 cm x 4 cm = 68 cm2.
The final side is the other longer side, also with an area of 68 cm2.
Now we just add up all the areas: 170 cm2 + 170 cm2 + 40 cm2 + 40 cm2 + 68 cm2 + 68 cm2 = 556 cm2 of wrapping paper!
So Jerry will need approximately 556 cm2 of wrapping paper to wrap the present. That should be enough to make his mother smile!
To find the surface area of the box, we need to calculate the area of each side and then add them together.
First, let's find the area of the bottom and top of the box. The bottom and top are both 10 cm wide and 17 cm long, so the area of each is 10 cm * 17 cm = 170 cm².
Next, let's find the area of the sides. The box has four sides, each measuring 10 cm (width) * 4 cm (height), so the area of each side is 10 cm * 4 cm = 40 cm². Since there are four sides, the total area of the sides is 4 * 40 cm² = 160 cm².
Finally, we add the area of the bottom, top, and sides together to get the total surface area: 170 cm² (bottom) + 170 cm² (top) + 160 cm² (sides) = 500 cm².
Therefore, Jerry will need 500 cm² of wrapping paper to wrap the present.
To calculate the surface area of the box, we need to find the area of each side and then sum them up.
The box has six sides:
- Two sides measuring 10 cm wide and 4 cm high: (10 cm * 4 cm) * 2 sides = 80 cm² * 2 = 160 cm².
- Two sides measuring 4 cm high and 17 cm long: (4 cm * 17 cm) * 2 sides = 68 cm² * 2 = 136 cm².
- Two sides measuring 10 cm wide and 17 cm long: (10 cm * 17 cm) * 2 sides = 170 cm² * 2 = 340 cm².
Now, we sum up the areas of all the sides:
160 cm² + 136 cm² + 340 cm² = 636 cm².
Therefore, Jerry will need 636 cm² of wrapping paper to wrap the present.