Determine the power output of a 2.0 g bee walking straight up a windowpane at 3.4 cm/s.
Assuming the bee's motion is primarily vertical, we can use the formula for gravitational potential energy:
PE = mgh
where m is the mass of the bee (2.0 g or 0.002 kg), g is the acceleration due to gravity (9.81 m/s^2), and h is the height the bee climbs in a second.
To find the height climbed, we can use the speed and the fact that the bee is moving vertically:
h = vt
where v is the speed (0.034 m/s) and t is the time (1 second)
h = (0.034 m/s)(1 s) = 0.034 m
Now we can calculate the potential energy gained by the bee:
PE = (0.002 kg)(9.81 m/s^2)(0.034 m) = 0.0068 J
Since this is the energy gained per second, the power output of the bee is:
P = 0.0068 J/s = 0.0068 W
Therefore, the power output of the bee walking straight up a windowpane at 3.4 cm/s is 0.0068 W.