A packing crate of weight 50N is placed on a plane inclined at 35degree from the horizontal. If the coefficient of static friction between the crate and the plane is 0.65, will the crate slide down the plane? At the will crate slide down the plane not use coefficient of static friction why?
To determine whether the crate will slide down the plane, we need to compare the force of gravity acting on the crate (its weight) to the force of friction between the crate and the plane.
The weight of the crate is given as 50N. We can find the component of this force acting parallel to the plane by multiplying it by the sine of the angle of inclination:
50N * sin(35°) ≈ 28.6N
This is the force that would cause the crate to slide down the plane if there were no friction.
The force of friction is given by the coefficient of static friction times the perpendicular force (the component of the weight acting perpendicular to the plane):
Ffriction = μ * Fperpendicular
Fperpendicular = 50N * cos(35°) ≈ 41.5N
Ffriction = 0.65 * 41.5N ≈ 27N
So the force of friction acting against the crate sliding down the plane is 27N.
Since the force of friction (27N) is greater than the force that would cause the crate to slide down the plane (28.6N), the crate will not slide down the plane.
We cannot answer whether the crate will slide down the plane without using the coefficient of static friction, as the force of friction is the only force acting against the crate sliding down the plane. The coefficient of static friction is a necessary factor in determining this force.