A packing crate of weight 50N is placed on a plane inclined at 35°from the horizontal. If the coefficient of static friction between the crate and the plane is 0.65, will the crate slide down the plane?

Question

Illustrate a physics laboratory scene. The main focus should be an experiment that is set up on a tabletop. The tabletop should host an inclined plane which is set at a 35° angle from the horizontal. On the incline, place a wooden crate whose weight corresponds to a force of 50N. Highlight the friction between the crate and the incline by adding an indicator of static friction, symbolized by sparks or notable resistance. But, do not add any text within the image. Lastly, ensure color contrast and lighting are balanced for an appealing image.

A packing crate of weight 50N is placed on a plane inclined at 35°from the horizontal. If the coefficient of static friction between the crate and the plane is 0.65, will the crate slide down the plane?

Answer 1

normal force = m g cos 35 = 50 cos 35 = 41 Newtons

so max friction force up slope = 0.65 * 41 = 26.6 N
Force down slope =50 sin 35 = 28.7 N
oh my, get out of the way

Answer 2

Normal force=mgcos35=50cos35=41N

So max friction force up slope =0.65N ×41 =26.6N
Force down slope=50Nsin35=28.7N

Answer 3

Yes, that's correct. The maximum friction force that can be exerted on the crate up the slope is 26.6 N, which is less than the force of gravity pulling it down the slope (28.7 N). Therefore, the crate will slide down the plane.

Answer 4

To determine whether the crate will slide down the plane or not, we need to compare the gravitational force pulling the crate down the incline with the maximum static friction force that can act on the crate.

1. Find the force pulling the crate down the incline:
The gravitational force pulling the crate down the incline can be calculated using the formula: F = m * g. Here, the mass (m) of the crate is irrelevant since it cancels out when we compare it with the force of friction. The acceleration due to gravity (g) is approximately 9.8 m/s^2. Therefore, the force pulling the crate down is F = 50N (weight of the crate).

2. Find the static friction force:
The maximum static friction force can be calculated using the formula: F_static_max = coefficient_of_static_friction * N, where N is the normal force acting on the crate perpendicular to the inclined plane. The normal force can be calculated as N = m * g * cos(angle of inclination), where the angle of inclination is 35°.

3. Calculate the maximum static friction:
Using the given coefficient of static friction (0.65) and the normal force, the maximum static friction force can be calculated as F_static_max = 0.65 * (m * g * cos(angle of inclination)).

Now, if the force pulling the crate down the incline (F) is greater than the maximum static friction force (F_static_max), the crate will slide down the plane. Otherwise, if F is less than or equal to F_static_max, the crate will not slide down.

Compare the gravitational force pulling the crate down (F) with the maximum static friction force (F_static_max). If F > F_static_max, the crate will slide down the plane. If F <= F_static_max, the crate will not slide down.

Plug in the values and do the calculations to find out the answer.

Answer 5

So max friction force up slope =0.65N

Force down slope=50Nsin35=28.7N

Answer 6

Yes, that's correct. The maximum friction force that can be exerted on the crate up the slope is 26.6 N, which is less than the force of gravity pulling it down the slope (28.7 N). Therefore, the crate will slide down the plane.

Answer 7

Well, if the crate slides down the plane, it might bring a whole new meaning to the term "crate escape"! But in all seriousness, let's do some calculations to find out if the crate will slide down.

To determine if the crate will slide, we need to compare the force of static friction with the force pulling the crate down the plane. The force pulling the crate down the plane is given by the weight of the crate, which is 50N.

The force of static friction can be calculated using the formula:

force of static friction = coefficient of static friction × normal force

Now, the normal force acting on the crate can be found by using the weight of the crate and the angle of inclination. The normal force is the component of the weight that acts perpendicular to the plane.

normal force = weight × cos(angle of inclination)

So, the normal force = 50N × cos(35°)

To find the force of static friction, we multiply the coefficient of static friction (0.65) by the normal force.

force of static friction = 0.65 × (50N × cos(35°))

Now, if the force of static friction is greater than or equal to the force pulling the crate down the plane (50N), then the crate will not slide.

I hope this explanation didn't slide over your head or make you inclined to leave! Let me crunch the numbers and give you the final answer.

Calculating... calculating...

After all the math, it turns out that the force of static friction is greater than the force pulling the crate down the plane. Therefore, the crate will not slide down. Phew! The crate must really love its spot on the inclined plane – it's guaranteed to stay put!

Just remember, sliding crates can be a slippery slope – always be careful when working with inclined surfaces!