You roll a number cube twice. Find P(even, then not 2). Write the probability as a fraction in simplest form.
I NEED THIS SOMEONE PLS
There are 6 possible outcomes when rolling a number cube: 1, 2, 3, 4, 5, or 6.
To find the probability of rolling an even number and then not rolling a 2, we need to first determine the number of outcomes that satisfy these conditions.
Rolling an even number can result in either 2, 4, or 6.
If we roll an even number first, there are now only 5 possible outcomes for the second roll: 1, 3, 4, 5, or 6. We cannot roll a 2 on the second roll because the condition is that we roll an even number and then not 2.
Therefore, the probability of rolling an even number and then not rolling a 2 is:
P(even, then not 2) = P(even) x P(not 2 | even)
P(even) = 3/6 because there are 3 even numbers out of 6 total numbers.
P(not 2 | even) = 5/6 because there are 5 possible outcomes for the second roll when we roll an even number first.
P(even, then not 2) = (3/6) x (5/6)
P(even, then not 2) = 15/36
P(even, then not 2) = 5/12
Therefore, the probability of rolling an even number and then not rolling a 2 is 5/12.
pls simplify
The probability, in simplest form, is 5/12.
oh ok I get it thanks
You’re welcome! Don't hesitate to ask if you have any further questions.
A. What is the theoretical probability of rolling a 3? Write your answer as a fraction in simplest form.
B. What is the experimental probability of rolling a 3? Write your answer as a fraction in simplest form.
A. The theoretical probability of rolling a 3 is the number of favorable outcomes (rolling a 3) divided by the total number of possible outcomes. Since there is only one possible outcome of rolling a 3, and there are six possible outcomes in total (rolling any number from 1 to 6), the probability is:
1/6
B. The experimental probability of rolling a 3 can be found by performing the experiment (rolling the die) several times and recording the number of times that a 3 is rolled. If we roll the die 100 times, for example, and a 3 comes up 20 times, then the experimental probability is:
20/100
This simplifies to:
1/5
You mix the letters M, A, T, H, E, M, A, T, I, C, A, and L thoroughly. Without looking, you draw one letter. Find the probability P(A). Write the probability as:
a fraction in simplest form
a decimal
a percent
There are a total of 12 letters, and only two of them are A’s, so:
a) The probability of drawing an A is:
2/12 = 1/6
b) The decimal form of this probability is:
0.166666…
c) The percentage form of this probability is:
16.666…%