The half reaction that occurs in a lead-acid battery are PbSO4(s)
+2e- Pb(s)+ ----- SO^2- E' =0.36VPbO2(s) + 4H^+(aq)+ SO + 2e PbSO(s) + 2H2O(l) ------+E° =
+1.69V Calculate the overall potential for the cell, E°cell
To calculate the overall potential for the cell, add the individual potentials for the two half reactions.
E°cell = E°(cathode) - E°(anode)
In this case, PbO2 is the cathode and Pb is the anode.
E°cell = (1.69 V) - (0.36 V) = 1.33 V