What is the molarity of the salt produced in the reaction of 200ml of 0.1m Hcl with 100ml of 0.500 m koh
To find the molarity of the salt produced, you need to first determine which salt is produced in the reaction. The equation for the reaction between HCl and KOH is:
HCl + KOH → KCl + H2O
This means that the salt produced is potassium chloride (KCl).
Next, you can use the following equation to calculate the moles of potassium chloride produced:
moles of KCl = (volume of HCl x molarity of HCl) / 1 + (volume of KOH x molarity of KOH) / 1
Using the values given in the question:
moles of KCl = (0.2 L x 0.1 mol/L) / 1 + (0.1 L x 0.5 mol/L) / 1
moles of KCl = 0.02 mol
Finally, you can use the following equation to calculate the molarity of the KCl solution:
molarity of KCl = moles of KCl / volume of solution in liters
The total volume of the solution is 200 mL + 100 mL = 0.3 L, so:
molarity of KCl = 0.02 mol / 0.3 L
molarity of KCl = 0.067 M
Therefore, the molarity of the KCl solution produced in the reaction is 0.067 M.