What is the minority of the salt produced in the reaction of 200ml of 0.1m Hcl with 100ml of 0.500 m koh
To solve this problem, you first need to write the balanced equation for the reaction between HCl and KOH:
HCl + KOH → KCl + H2O
This tells you that when the two solutions are mixed, KCl (potassium chloride) and water will be produced.
Next, you need to calculate the moles of HCl and KOH present:
moles of HCl = concentration (in mol/L) × volume (in L) = 0.1 × 0.2 = 0.02 mol
moles of KOH = concentration (in mol/L) × volume (in L) = 0.5 × 0.1 = 0.05 mol
According to the balanced equation, the reaction will use up 0.02 mol of HCl and 0.02 mol of KOH (since they react in a 1:1 ratio). This leaves 0.03 mol of KOH remaining. Therefore, the minority product is HCl, since all of it will be consumed in the reaction, while some KOH will be left over.