What is the sum of the arithmetic series 18 sigma t=1 (5t-4)?
In this image, the lower limit of the summation notation is "t = 1"
The sum of an arithmetic series can be found by using the formula:
S_n = (n/2) * [2a + (n-1)d]
where S_n is the sum of the first n terms of the series, a is the first term, d is the common difference, and n is the number of terms in the series.
In this case, we have:
a = 5(1)-4 = 1
d = 5
n = 18
So we can plug in these values into the formula:
S_18 = (18/2) * [2(1) + (18-1)(5)]
= 9 * [2 + 17(5)]
= 9 * 89
= 801
Therefore, the sum of the arithmetic series is 801.