A ball is thrown from straight up from a height of 1.25 meters above the ground with an initial velocity of 30 meters per second. What is the max height? When does the ball reach its max height?
v^2 = 2gh
so plug in your numbers to find h
or, the height is
y = 1.25 + 30t - 4.9t^2
max height is at the vertex, which is when t = -n/2a = 30/9.8