Factorise completely
(A) 2p^2-5p-3=0
(B)x^2-36=0
(A) To factorise 2p^2-5p-3=0, we need to find two numbers that multiply to -6 and add to -5. These numbers are -6 and +1. Therefore,
2p^2 - 5p - 3 = 0
2p^2 - 6p + p - 3 = 0
2p(p-3) + 1(p-3) = 0
(2p+1)(p-3) = 0
So, the factors of 2p^2-5p-3=0 are (2p+1)(p-3).
(B) To factorise x^2-36=0, we can use the difference of squares formula, which states a^2 - b^2 = (a+b)(a-b).
Therefore,
x^2 - 36 = 0
(x+6)(x-6) = 0
So, the factors of x^2-36=0 are (x+6)(x-6).