David wants to build a pen for his girl. He wants the area of the pan to be 48 ft.² if the length and width of the pen are whole numbers which of the following could be the perimeter of the pen
We can start by finding all possible combinations of length and width that give an area of 48 ft². These are:
1 ft x 48 ft
2 ft x 24 ft
3 ft x 16 ft
4 ft x 12 ft
6 ft x 8 ft
Next, we can calculate the perimeter for each of these combinations:
Perimeter of 1 ft x 48 ft pen = 2(1 ft + 48 ft) = 98 ft
Perimeter of 2 ft x 24 ft pen = 2(2 ft + 24 ft) = 52 ft
Perimeter of 3 ft x 16 ft pen = 2(3 ft + 16 ft) = 38 ft
Perimeter of 4 ft x 12 ft pen = 2(4 ft + 12 ft) = 32 ft
Perimeter of 6 ft x 8 ft pen = 2(6 ft + 8 ft) = 28 ft
Therefore, the possible perimeters are 52 ft, 38 ft, 32 ft, and 28 ft.