Determine the number of atoms for each element on both the reactant and product sides of an equation
C5H12 + 6O2 ---> 6CO2 + H2O
Reactant side:
- C: 5 atoms
- H: 12 atoms
- O: 12 atoms
Product side:
- C: 6 atoms
- H: 2 atoms
- O: 13 atoms
C5H12 + 6O2 ---> 6CO2 + H2O
- C: 5 atoms
- H: 12 atoms
- O: 12 atoms
Product side:
- C: 6 atoms
- H: 2 atoms
- O: 13 atoms