A long rope is fixed at one end, and the free end is made to oscillate in one plane at right angles to the rope with a frequency of 4hz.the successive crest are o. 6meter apart, calculate the speed of the waves and for what frequency would the wave length be 30cm
Given the frequency (f) of the oscillation is 4 Hz, and the distance between the successive crests (wavelength, λ) is 0.6 meters.
We can calculate the speed of the waves (v) using the formula:
v = f * λ
Substituting the given values, we get:
v = 4 Hz * 0.6 meters = 2.4 meters/second
Now, let's find the frequency (f') required for the wavelength (λ') to be 30 cm (or 0.3 meters). We will use the same formula as before, but rearranged to find the frequency:
f' = v / λ'
We already know the wave speed (v) from our previous calculations, so we can plug in the values and calculate the new frequency:
f' = 2.4 meters/second / 0.3 meters = 8 Hz
So, the speed of the waves is 2.4 meters/second, and for a wavelength of 30 cm, the frequency would need to be 8 Hz.