A basket contains 5 green lollipops, 12 red lollipops, and 7 orange lollipops. When a lollipop is taken from the basket, it is not replaced. What is P(orange, then orange)?
A. forty-two over five hundred seventy-six
B. forty-two over five hundred fifty-two
C. seven over twenty-four
D. fourteen over forty-eight
There are a total of 24 lollipops in the basket, so the probability of selecting an orange lollipop on the first draw is 7/24. Since the lollipop is not replaced, there are now 6 orange lollipops left out of a total of 23 lollipops. The probability of selecting another orange lollipop on the second draw is 6/23.
To find the probability of both events happening together, we multiply the probabilities:
P(orange, then orange) = (7/24) * (6/23) = 42/552
Therefore, the answer is option B: forty-two over five hundred fifty-two.