Thomas is facing towards town A, which is at a bearing of 300 degrees from him.
If he turns 125 degrees clockwise, he will be facing towards town B.
What is the bearing of town B from Thomas?
AAAaannndd the bot gets it wrong yet again!
(300 + 125) = 425
425-360 = 65°
To determine the bearing of town B from Thomas, we need to add the clockwise turn of 125 degrees to the initial bearing of town A.
The initial bearing of town A is 300 degrees.
To that, we add the clockwise turn of 125 degrees:
300 degrees + 125 degrees = 425 degrees
Therefore, the bearing of town B from Thomas is 425 degrees.
To determine the bearing of town B from Thomas, we need to add the angle by which Thomas turned clockwise to the original bearing towards town A.
Thomas initially faces towards town A at a bearing of 300 degrees. If he turns 125 degrees clockwise, we can add that to the original bearing:
300 degrees + 125 degrees = 425 degrees
Therefore, the bearing of town B from Thomas is 425 degrees.
To solve this problem, we need to use the concept of bearings, which is the angle between a line and a fixed reference direction.
Let's start by drawing a diagram:
N
|
W--------|--------E
|
S
From the problem statement, we know that Thomas is facing towards town A, which is at a bearing of 300 degrees from him. This means that the line connecting Thomas and town A makes an angle of 300 degrees with the reference direction, which we can take to be the North direction.
Now, if Thomas turns 125 degrees clockwise, he will be facing towards town B. This means that the line connecting Thomas and town B will make an angle of (300 + 125) = 425 degrees with the North direction.
However, bearings are usually expressed as angles measured clockwise from the North direction, so we need to subtract this angle from 360 degrees to get the bearing of town B from Thomas:
Bearing of town B = 360 - 425 = 35 degrees
Therefore, the bearing of town B from Thomas is 35 degrees.