The bearing of Q from P is 300 degrees and the bearing of R from Q is 210 degrees. If Q is equidistance from P and R, find the bearing of R from P.?
A man start from a point A and walks 1000m on a bearing of 025°. How far north is he from his starting point.?
R's bearing from P is 270-θ, where
tanθ = √2/(1+√3)
your 2nd question:
cos 25 = y/1000
y = 1000cos25 = ....
To find the bearing of R from P, we need to add the bearings of Q from P and R from Q.
Given that the bearing of Q from P is 300 degrees and the bearing of R from Q is 210 degrees, we can proceed as follows:
1. Start with the bearing of Q from P, which is 300 degrees.
2. Add the bearing of R from Q, which is 210 degrees.
300 degrees + 210 degrees = 510 degrees
3. The resulting value, 510 degrees, is the bearing of R from P.
Therefore, the bearing of R from P is 510 degrees.