Two geometric progressions have equal sums to infinity. Their first terms are 27 and 36 respectively. If the common ratio of the first is 3/4, find the common ratio of the other

Let the common ratio of the second geometric progression be 'k'.

The sum to infinity of the first progression is:

S1 = a1/(1-r1) = 27/(1-3/4) = 108

The sum to infinity of the second progression is:

S2 = a2/(1-k) = 36/(1-k)

Given that S1 = S2, we have:

27/(1-3/4) = 36/(1-k)

Simplifying this expression, we get:

k = 1 - (27/36)(1-3/4) = 9/16

Therefore, the common ratio of the second geometric progression is 9/16.