Write an equation for the reaction between iron fillings and dilute tetraoxosulphate (VI) acid.
The equation for the reaction between iron fillings and dilute tetraoxosulphate (VI) acid is:
Fe(s) + H2SO4(aq) → FeSO4(aq) + H2(g)
In this reaction, iron (Fe) reacts with dilute tetraoxosulphate (VI) acid (H2SO4) to form iron(II) sulphate (FeSO4) and hydrogen gas (H2).
Yes 👍
I don't know
Sure, here's my equation:
Iron fillings + Dilute tetraoxosulphate (VI) acid -> Clown magic + Lots of fizzles + Iron(II) tetraoxosulphate (VI) + Hilarity
But in all seriousness, the equation for this reaction is:
Fe(s) + H2SO4(aq) -> FeSO4(aq) + H2(g)
Hope that brings a smile to your face!
To write the equation for the reaction between iron fillings and dilute tetraoxosulphate (VI) acid, we need to first understand the chemical formulas of the substances involved.
The chemical formula for iron is Fe, and for dilute tetraoxosulphate (VI) acid (also known as sulfuric acid), it is H2SO4.
Now, let's examine the reaction. When iron reacts with sulfuric acid, it undergoes a displacement reaction, where the iron replaces the hydrogen in the acid. This can be represented by the following chemical equation:
Fe + H2SO4 -> FeSO4 + H2
In this equation, Fe represents iron, H2SO4 represents sulfuric acid, FeSO4 represents iron(II) sulfate, and H2 represents hydrogen gas.
This balanced equation represents the reaction between iron fillings and dilute tetraoxosulphate (VI) acid, also known as sulfuric acid.