What is the gas given off when zinc reacts with dilute tetraoxosulphate vi acid
The gas given off when zinc reacts with dilute tetraoxosulphate vi acid is hydrogen.
hydrogen
When zinc reacts with dilute tetraoxosulphate VI acid (also known as sulfuric acid), the gas given off is hydrogen gas (H2). The reaction can be represented by the following equation:
Zn + H2SO4 -> ZnSO4 + H2
The gas given off when zinc reacts with dilute tetraoxosulphate VI acid is hydrogen gas (H2).
To determine this, we need to know the chemical equation for the reaction between zinc and tetraoxosulphate VI acid. The chemical equation for this reaction can be written as:
Zn + H2SO4 → ZnSO4 + H2
In this equation, zinc (Zn) reacts with tetraoxosulphate VI acid (H2SO4) to form zinc sulphate (ZnSO4) and hydrogen gas (H2) as a product.
So, when zinc reacts with dilute tetraoxosulphate VI acid, hydrogen gas is given off.