2ax -4bx+2by factorise completely
To factorize 2ax - 4bx + 2by completely, we can first factor out the common factor of 2:
2ax - 4bx + 2by = 2(a-b)y - 2bx
Next, we can factor out the common factor of -2b:
2(a-b)y - 2bx = -2b(x - (a-b)y)
Therefore, the complete factorization of 2ax - 4bx + 2by is:
2ax - 4bx + 2by = -2b(x - (a-b)y)