The sum of three consecutive numbers odd numbers is one hundred and eleven
What is the smallest of the three numbers
Let's assume that the smallest of the three consecutive odd numbers is x.
Then, the next two odd numbers would be x+2 and x+4.
According to the problem, the sum of these three numbers is 111:
x + (x+2) + (x+4) = 111
Simplifying the equation:
3x + 6 = 111
Subtracting 6 from both sides:
3x = 105
Dividing both sides by 3:
x = 35
Therefore, the smallest of the three consecutive odd numbers is 35.
1113 = 37. So,
35+37+39 = 111
35 is the smallest