A set of springs have 10N of force applied to them. By how much would a spring extend if they had the spring constants of 1.5N/m?
a) 0.15m
b) 0.66m
c) 15m
We can use Hooke's Law to solve this problem. Hooke's Law states that the force applied to a spring is proportional to the extension or compression of the spring, and the constant of proportionality is the spring constant.
The formula for Hooke's Law is:
F = kx
where F is the force applied to the spring, k is the spring constant, and x is the extension or compression of the spring.
In this problem, we are given the force applied to the spring (10N) and the spring constant (1.5N/m). We can rearrange the formula to solve for x:
x = F/k
Substituting the values we have:
x = 10N / 1.5N/m
x = 6.67m
Therefore, the spring would extend by 6.67m if a force of 10N is applied to a spring with a spring constant of 1.5N/m. The answer is not one of the options given, so it is possible that there is a mistake in the problem statement.