the gold bar hs a trapezium cross-sectional area.
gold has a density of 19.3 grams per cm cubed.
work out the mass of the gold bar.
give your answer in kilograms.
Answer:
Let the base of the trapezium be 'a' cm and the height of the trapezium be 'h' cm.
The area of the trapezium = (a + h) x h/2
Therefore, the mass of the gold bar = (a + h) x h/2 x 19.3 g/cm3
= (a + h) x h x 9.65 g/cm2
= (a + h) x h x 0.009650 kg/cm2
= 0.009650 x (a + h) x h kg
= 0.009650 x (a + h) x h/1000 kg
= 0.000009650 x (a + h) x h kg
= 0.000009650 x (a + h) x h/1000 kg (in kilograms)