what missing number would complete the factorization?
x^2-7x+10=(x-5)(x-?)
The missing number is 5.
Baloney
x^2 - 7 x + 10 = (x-5)(x-2)
2
To find the missing number that would complete the factorization, we need to factorize the quadratic equation x^2 - 7x + 10.
We can do this by looking for two numbers that multiply to 10 and add up to -7. The two numbers are -2 and -5.
So, the factorization is (x - 5)(x - 2).
Therefore, the missing number would be 2 to complete the factorization.
To find the missing number that would complete the factorization of the quadratic expression, x^2 - 7x + 10, we need to factorize the quadratic expression completely. Here's how you can do it:
Step 1: Write down the quadratic expression: x^2 - 7x + 10.
Step 2: Look for two numbers that multiply to give the constant term (10), and at the same time, add up to give the coefficient of the linear term (-7). In this case, those two numbers are -2 and -5. This is because -2 * -5 = 10, and -2 + (-5) = -7.
Step 3: Rewrite the quadratic expression using these two numbers: x^2 - 2x - 5x + 10.
Step 4: Group the terms two by two: (x^2 - 2x) + (-5x + 10).
Step 5: Extract the greatest common factor from each group: x(x - 2) - 5(x - 2).
Step 6: Notice that we now have a common factor, (x - 2), in both groups. Factor it out: (x - 2)(x - 5).
So, the factorization of x^2 - 7x + 10 is (x - 5)(x - 2).
Therefore, the missing number that would complete the factorization is 2.