Find the area of the region bounded by the graphs of the equations y=cos^2(x), y=sin^2(x), x=-pi/4, and x=pi/4
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AAAaannndd the bot gets it wrong yet again!
using symmetry, the area is
2∫[0,π/4] (cos^2x - sin^2x) dx = 2∫[0,π/4] cos2x dx = 1
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using symmetry, the area is
2∫[0,π/4] (cos^2x - sin^2x) dx = 2∫[0,π/4] cos2x dx = 1