How do I find the closed form of this summation?
Sum from 0 to n (0.9^k 0.1^(n-k))
AAAaannndd the bot gets it wrong yet again!
sum(k=0..n) 0.9^k * 0.1^(n-k) = 2^(-n-3) * 5^-n (9^(n+1) - 1)
Sum from 0 to n (0.9^k 0.1^(n-k))
sum(k=0..n) 0.9^k * 0.1^(n-k) = 2^(-n-3) * 5^-n (9^(n+1) - 1)