Find the area of each trapezoid, given the bases b1
b sub 1and b2
b sub 2and height h .
b1b2h=3 m=7 m=3 m
table with 3 rows and 2 columns row1 column 1 b sub 1 column 2 equals 3 m row2 column 1 b sub 2 column 2 equals 7 m row3 column 1 h column 2 equals 3 m end table
b1b2h=11 in.=16 in.=9 in.
table with 3 rows and 2 columns row1 column 1 b sub 1 column 2 equals 11 in row2 column 1 b sub 2 column 2 equals 16 in row3 column 1 h column 2 equals 9 in end table
b1b2h=5.6 cm=8.5 cm=6 cm
table with 3 rows and 2 columns row1 column 1 b sub 1 column 2 equals 5.6 cm row2 column 1 b sub 2 column 2 equals 8.5 cm row3 column 1 h column 2 equals 6 cm end table
b1b2h=312 ft=214 ft=2 ft
table with 3 rows and 2 columns row1 column 1 b sub 1 column 2 equals 312 ft row2 column 1 b sub 2 column 2 equals 214 ft row3 column 1 h column 2 equals 2 ft end table
Answer: The area of each trapezoid is:
3 m: 21 m2
11 in.: 108 in.2
5.6 cm: 33.6 cm2
312 ft: 428 ft2